Function overloading in c++

Function overloading in C++

Function overloading in C++ allows you to specify more than one definition for a function name in the same scope,.

An overloaded declaration is a declaration that had been declared with the same name as a previously declared in the same scope, except that both declarations have different arguments and obviously different definition, that is implementation.

When you call an overloaded function, the compiler determines the most appropriate definition to use by comparing the argument types you used to call the function with the parameter types specified in the definitions. The process of selecting the most appropriate overloaded function or operator is called overload resolution.

Function overloading in C++:

You can have multiple definitions for the same function name in the same scope. The definition of the function must differ from each other by the types and/or the number of arguments in the argument list. You can not overload function declarations that differ only by return type.

Following is the example where same function print() is being used to print different data types:

#include <iostream>
using namespace std;
 
class printData 
{
   public:
      void print(int i) {
        cout << "Printing int: " << i << endl;
      }

      void print(double  f) {
        cout << "Printing float: " << f << endl;
      }

      void print(char* c) {
        cout << "Printing character: " << c << endl;
      }
};

int main(void)
{
   printData pd;
 
   // Call print to print integer
   pd.print(5);
   // Call print to print float
   pd.print(500.263);
   // Call print to print character
   pd.print("Hello C++");
 
   return 0;
}

This code is compiled and executed, it produces the following result:

Printing int: 5 Printing float: 500.263 Printing character: Hello C++

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