by admin | May 24, 2015 | sem1
Unit cell Unit cell can be considered as the building block of a crystal. It has the same symmetry as the entire crystal. When we arrange the unit cell in 3D, we get the bulk crystal. In other words, it can be described...
by admin | May 24, 2015 | sem1
Projection of Truncated Solids Development of a truncated prism The method of obtaining the development of a truncated prism is shown in figure 1. Step 1: Draw the stretch-out line in the front view, along the base of the prism and equal in length to the...
by admin | May 24, 2015 | sem1
Sections of Solids Sample Problem 1:A hexagonal prism, side of base 30 mm and axis 60 mm long, rests with its base on HP such that one of its rectangular faces is parallel to VP. A section plane perpendicular to HP and parallel to VP cuts the prism at a distance of 10...
by admin | May 24, 2015 | sem1
Projections of Cylinder Sample Problem 1:Draw the projections of a cylinder, base 30 mm diameter and axis 40 mm long , resting with a point of its base circle on HP such that the axis is making an angle of 30º with HP and parallel to VP. Steps for Projections of...
by admin | May 24, 2015 | sem1
Intersection of Surfaces Sample Problem 1: The front view of a cone resting on its base on HP is an equilateral triangle of 75 mm side with one side horizontal. It is penetrated by a square prism of side 25 mm. The rectangular faces of the prism are equally inclined...
by admin | May 24, 2015 | sem1
Development of lateral Surfaces of Two Intersecting Solids Sample Problem 1: A vertical square prism of side of base 45 mm and height 80 mm rests on HP with its faces equally inclined to VP. it is pierced centrally by a horizontal cylinder of 40 mm diameter and 80 mm...
